A of Rs. 20,000 is borrowed by Heena 2 years an interest of 8% compounded annually. Find the Compound Interest (C.I.) and the amount she has to pay the end of 2 years.1728332823663200 (2024)
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A sum of Rs.20,000 is borrowed by Heena for 2 years at an interest of 8% compounded annually. Find the Compound Interest (C.I.) and the amount she has to pay at the end of 2 years.
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2
Without using the formula for compound interest solve the following problem. A sum of Rs 20,000 is borrowed by Heena for 2 years at an interest of 8% compounded annually. Find the Compound Interest (C.I.) and the amount she has to pay at the end of 2 years.
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3
If a sum of ₹ 20,000 is borrowed by Heena for 2 years at an interest of 8% compounded annually, then the amount she has to pay at the end of 2 years is
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4
If Satish borrows a sum of ₹ 15,000 for 2 years at an interest of 15%, compounded annually, then the amount he has to pay at the end of 2 years is
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5
Vikram borrowed Rs. 20,000 for 412 years at 10% per annum, compound annually. How much compound interest would he pay at the end of 412 years?
A = 20000(1 + 0.18/1)^(1*4) A = 20000(1 + 0.18)^4 A = 20000(1.18)^4 A = 20000 * 2.9372 A ≈ 58744 So, the total amount to be paid back after 4 years is approximately 58744. Divide the total amount by 4 to find the value of each instalment.
What will Rs 25000 amounts to in two years at Compound Interest if the rates for successive years be 4 % and 5 % per year. A=P⋅(1+R1100)N1⋅(1+R2100)N2... =27300.
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